Nelson Touboul Jan. 8, 2015
Tyler Grosman
Balloon Toss Lab
Purpose:
To investigate the effect of mass upon the impact force in a collision.
Procedure:
1) A water balloon is thrown (or dropped from) approximately 10 feet up into the air, caught and observed to not break. The same balloon is thrown 30-40 feet up into the air, and observed to break.
2) A not very massive (under filled) water balloon is thrown (or dropped from) about 20 feet up into the air, caught by the teacher and observed to not break. A very massive (overfilled) water balloon is thrown about the same distance up into the air, caught and observed to break.
3) A water balloon is thrown (or dropped from) approximately 50 feet up into the air, caught using a cradling motion, and observed not to break. The same water balloon is thrown about the same distance up into the air, allowed to hit the ground and observed to break. Students record their observations, identifying the independent variable (m, F, ∆t), the constant quantities, and the dependent variable for each demonstration.
Data:
Trial 1: small balloon (200 grams) 0.9 secs
Trial 2: medium balloon (247 grams) 0.83 secs
Trial 3: bigger balloon (365 grams) 0.96 sec
Trial 4: largest balloon (450 grams) 0.9 secs- Broke
Tyler Grosman
Balloon Toss Lab
Purpose:
To investigate the effect of mass upon the impact force in a collision.
Procedure:
1) A water balloon is thrown (or dropped from) approximately 10 feet up into the air, caught and observed to not break. The same balloon is thrown 30-40 feet up into the air, and observed to break.
2) A not very massive (under filled) water balloon is thrown (or dropped from) about 20 feet up into the air, caught by the teacher and observed to not break. A very massive (overfilled) water balloon is thrown about the same distance up into the air, caught and observed to break.
3) A water balloon is thrown (or dropped from) approximately 50 feet up into the air, caught using a cradling motion, and observed not to break. The same water balloon is thrown about the same distance up into the air, allowed to hit the ground and observed to break. Students record their observations, identifying the independent variable (m, F, ∆t), the constant quantities, and the dependent variable for each demonstration.
Data:
Trial 1: small balloon (200 grams) 0.9 secs
Trial 2: medium balloon (247 grams) 0.83 secs
Trial 3: bigger balloon (365 grams) 0.96 sec
Trial 4: largest balloon (450 grams) 0.9 secs- Broke
Observations:
We observed that balloons balloons of lower mass could withstand more force while catching them and that balloons possessing larger masses could not withstand as much force do to the amount of force that they already carried.
We observed that balloons balloons of lower mass could withstand more force while catching them and that balloons possessing larger masses could not withstand as much force do to the amount of force that they already carried.
Questions:
2. a What effect does a ten-fold increase in ∆time have upon the subsequent force which is required to change an object's momentum (assuming other quantities are constant)?
-It reduces the force tenfold. Rows a. and C. demonstrate this cause and effect.
-If the mass is increased five-fold, then the force is increased 2.5-fold. Rows a. and b. apply to this cause and effect.
-If the velocity is increased two-fold, then the force in increased two-fold. Rows “E” and “F” exemplify this concept. When the time is decreased, the force increases but when the time increases then the force would need to decrease in order to prevent the balloon from breaking.
E. (-1600)(0.5)=-800 F. (-400)(2)=-800
Conclusion:
Nelson Touboul
Using my lacrosse skills, I was able to minimize the impulse by increasing the time of impact. As the balloon approached my hand, I slowed it down with a cradle motion so that the balloon would not burst. The balloon with the the largest mass broke. I came to the conclusion that the larger the mass, the larger the force will be. In other words, the larger the mass, the more likely it will burst. By increasing the time, the force inevitably was decreased which decreased the impulse. Furthermore, this prevented most of the balloons from bursting.
Conclusion:
Tyler Grosman
From the data collected, we were able to conclude that less time for each trial resulted in larger forces on the balloons when not cradled into a catch, but when cradled, it resulted in more time being added to each of the falls. This minimized the force on the balloons as they fell, allowing for them to stay intact and not break on contact with our hands. The mass of the balloons was also a factor. The larger the balloon, the more time and minimization of force upon the balloon was necessary. Smaller balloons carry less force during the fall so it is not necessary to minimize the force upon the balloons because they will not pop. Larger balloons need to have the force brought down when catching them because they possess more force during the fall than balloons with smaller masses.
2. a What effect does a ten-fold increase in ∆time have upon the subsequent force which is required to change an object's momentum (assuming other quantities are constant)?
-It reduces the force tenfold. Rows a. and C. demonstrate this cause and effect.
- (.1)(200)=20 C. (.1)(-40)=-4
-If the mass is increased five-fold, then the force is increased 2.5-fold. Rows a. and b. apply to this cause and effect.
- (2.5)(-200)=-500 B. (2.5)(-20)=-50
-If the velocity is increased two-fold, then the force in increased two-fold. Rows “E” and “F” exemplify this concept. When the time is decreased, the force increases but when the time increases then the force would need to decrease in order to prevent the balloon from breaking.
E. (-1600)(0.5)=-800 F. (-400)(2)=-800
Conclusion:
Nelson Touboul
Using my lacrosse skills, I was able to minimize the impulse by increasing the time of impact. As the balloon approached my hand, I slowed it down with a cradle motion so that the balloon would not burst. The balloon with the the largest mass broke. I came to the conclusion that the larger the mass, the larger the force will be. In other words, the larger the mass, the more likely it will burst. By increasing the time, the force inevitably was decreased which decreased the impulse. Furthermore, this prevented most of the balloons from bursting.
Conclusion:
Tyler Grosman
From the data collected, we were able to conclude that less time for each trial resulted in larger forces on the balloons when not cradled into a catch, but when cradled, it resulted in more time being added to each of the falls. This minimized the force on the balloons as they fell, allowing for them to stay intact and not break on contact with our hands. The mass of the balloons was also a factor. The larger the balloon, the more time and minimization of force upon the balloon was necessary. Smaller balloons carry less force during the fall so it is not necessary to minimize the force upon the balloons because they will not pop. Larger balloons need to have the force brought down when catching them because they possess more force during the fall than balloons with smaller masses.