Purpose:
The purpose of this lab is to determine the speed of an individual object that is constantly in motion. The reason we are trying to find this is so that we are able to calculate the average times for objects in motion within a fixed distance. Procedure: • Chose a fixed distance for the mechanical cars: 150 cm • Timed the car for the duration of its travels across the 150 cm gap (3 times) • Recorded each trial with their individual and varying sets of data • Found the average time of travel within the fixed distanced for the car • Chose a fixed distance for a jogger: 10 yards • Timed the jogger for the duration of their travels across the 10 yard gap (3 times) • Recorded each trial with their individual and varying sets of data • Found the average time of travel within the fixed distance for the jogger Results: Data/Observation Car: Trial 1: Distance-150 cm; Time-4.3 cm/sec Trial 2: Distance-150 cm; Time-4.4 cm/sec Trial 3: Distance-150 cm; Time-3.8 cm/sec Jogger: Trial 1: Distance-10 yards; Time-2.01 yds/sec Trial 2: Distance-10 yards; Time-2.14 yds/sec Trial 3: Distance-10 yards; Time-2.37 yds/sec Calculations: 150 cm/4.3 seconds=34.8837 cm/sec 150 cm/4.4 seconds=34.0909 cm/sec 150 cm/3.8 seconds=39.4737 cm/sec Average: (34.8837+34.0909+39.4737)/3=36.1494 cm/sec 10 yds/2.01 seconds=4.9751 yds/sec 10 yds/2.14 seconds=4.6729 yds/sec 10 yds/2.37 seconds=4.2194 yds/sec Average: (4.9751+4.6729+4.2194)/3=4.6225 yds/sec Analysis: Equation: D/T=Speed Sample calculations shown above in “Results: Data/Observation” Discussion/Conclusion: Tyler: In our experiment, we were able to record carrying sets of data even though we did not change the distance of each trial for the car and the jogger. We were able to figure out the speeds of an object that was constantly in motion while still being able to create a graph with our different sets of data.The only reason that we obtained a smaller margin for time variations was due to the fact that we did not change the distance, but I feel that the concepts of the lab were still firmly grasped by my partners and I. Elmira : After calculating the speed of the toy car, which was also the slope of the graph which corresponded to the toy car, by dividing the speed traveled by the amount of time it took to achieve that distance, we got 34.88 sec.’s. After calculating the speed of the walking person, which also corresponded to the slope of the graph of the walking person, by dividing the distance traveled by the amount of time it took to achieve that distance, we got 4.974 sec.’s. Due to these results, we concluded that the walker was faster than the toy car. lol #grammargod Graph: y=mx+b d=mt+b r=m d=rt r=d/t Slope: Jogger= 4.974, Car= 34.88 |
Error Analysis:
We had limitations in this lab that resulted in some sort of error. We had limitations on our ability to time the trials properly. there was no device to accurate measure the time that the car and the jogger crossed the line. there was also no way of making sure that the jogger, but more importantly the car, were perfectly straight with the line to ensure the fastest time of arrival for each object of constant motion in question. Our procedure was an obvious error due to the fact that we did not change the distances of each trial for the jogger and the car. These were the errors in our experiment.
Percent Error:
Class average: 32.1499
Our average: 36.15
(32.1499-36.15)/32.1499=0.12442 x 100=12.442
We had limitations in this lab that resulted in some sort of error. We had limitations on our ability to time the trials properly. there was no device to accurate measure the time that the car and the jogger crossed the line. there was also no way of making sure that the jogger, but more importantly the car, were perfectly straight with the line to ensure the fastest time of arrival for each object of constant motion in question. Our procedure was an obvious error due to the fact that we did not change the distances of each trial for the jogger and the car. These were the errors in our experiment.
Percent Error:
Class average: 32.1499
Our average: 36.15
(32.1499-36.15)/32.1499=0.12442 x 100=12.442